b^2-3by-40y^2=

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Solution for b^2-3by-40y^2= equation:


Simplifying
b2 + -3by + -40y2 = 0

Reorder the terms:
-3by + b2 + -40y2 = 0

Solving
-3by + b2 + -40y2 = 0

Solving for variable 'b'.

Factor a trinomial.
(b + -8y)(b + 5y) = 0

Subproblem 1

Set the factor '(b + -8y)' equal to zero and attempt to solve: Simplifying b + -8y = 0 Solving b + -8y = 0 Move all terms containing b to the left, all other terms to the right. Add '8y' to each side of the equation. b + -8y + 8y = 0 + 8y Combine like terms: -8y + 8y = 0 b + 0 = 0 + 8y b = 0 + 8y Remove the zero: b = 8y Simplifying b = 8y

Subproblem 2

Set the factor '(b + 5y)' equal to zero and attempt to solve: Simplifying b + 5y = 0 Solving b + 5y = 0 Move all terms containing b to the left, all other terms to the right. Add '-5y' to each side of the equation. b + 5y + -5y = 0 + -5y Combine like terms: 5y + -5y = 0 b + 0 = 0 + -5y b = 0 + -5y Remove the zero: b = -5y Simplifying b = -5y

Solution

b = {8y, -5y}

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